Work Power and Energy 5 Question 13

(1980)

(a) the displacement of the particle when its velocity is zero, and

(b) the work done by the force in the first 6s.

Match the Column

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Answer:

Correct Answer: 16. (a) zero (b) zero

Solution:

  1. Given, t=x+3 or x=(t3)

x=(t3)2=t26t+9

Differentiating this equation with respect to time, we get

 velocity v=dxdt=2t6

(a) v=0 when 2t6=0 or t=3s

Substituting in Eq. (i), we get

or

x=0x=0

i.e. displacement of particle when velocity is zero is also zero.

(b) From Eq. (iii), speed of particle at t=0 is

vi=|v|=6m/s

and at t=6s

vf=|v|=6m/s

From work energy theorem,

Work done = change in kinetic energy

=12m[vf2vi2]=12m[(6)2(6)2]=0



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