Work Power and Energy 5 Question 12

15. A string, with one end fixed on a rigid wall, passing over a fixed frictionless pulley at a distance of 2m from the wall, has a point mass M=2kg attached to it at a distance of 1m from the wall. A mass m=0.5kg attached at the free end is held at rest so that the string is horizontal between the wall and the pulley and vertical beyond the pulley. What will be the speed with which the mass M will hit the wall when the mass m is released? (Take g=9.8m/s2 )

(1985,6M)

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Answer:

Correct Answer: 15. 3.29m/s

Solution:

  1. Let M strikes with speed v. Then, velocity of m at this instant will be vcosθ or 25v. Further M will fall a distance of 1m while m will rise up by (51)m. From energy conservation, decrease in potential energy of M= increase in potential energy of m +increase in kinetic energy of both the blocks.

or (2)(9.8)(1)=(0.5)(9.8)(51)+12×2×v2

+12×0.5×2v52

Solving this equation, we get, v=3.29m/s.



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