Work Power and Energy 1 Question 4

5. The work done on a particle of mass m by a force, Kx(x2+y2)3/2i^+y(x2+y2)3/2j^

(K being a

constant of appropriate dimensions), when the particle is taken from the point (a,0) to the point (0,a) along a circular path of radius a about the origin in the xy plane is

(2013 Adv.)

(a) 2Kπa

(b) Kπa

(c) Kπ2a

(d) 0

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Answer:

Correct Answer: 5. (d)

Solution:

  1. r=OP=xi^+yj^

F=k(x2+y2)3/2(xi^+yj^)=kr3(r)

Since, F is along r or in radial direction.

Therefore, work done is zero.



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