SATHEE: Work Power and Energy 1 Question 10

Work Power and Energy 1 Question 10

11. A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses $0.36 k g$ and $0.72 k g$ . Taking $g = 10 m s^{- 2}$ , find the work done (in Joule) by string on the block of mass $0.36 k g$ during the first second after the system is released from rest.

(2009)

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Answer:

Correct Answer: 11. 8

Solution:

$a = \frac{Net pulling force}{Total mass}$

$= \frac{0.72 g - 0.36 g}{0.72 + 0.36} = \frac{g}{3}$

$\begin{aligned} s = \frac{1}{2} a t^{2} = \frac{1}{2} \frac{g}{3} (1)^{2} = \frac{g}{6} \\ T - 0.36 g = 0.36 a = 0.36 \frac{g}{3} 0.36 k g \\ ∴ T = 0.48 g \\ Now, W_{T} = T S \cos 0^{\circ} \\ (on 0.36 k g mass) \\ = 0.08 (g^{2}) = 0.08 (10)^{2} = 8 J \end{aligned}$

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Work Power and Energy 1 Question 10

11. A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses 0.36kg and 0.72kg. Taking g=10ms−2, find the work done (in Joule) by string on the block of mass 0.36kg during the first second after the system is released from rest.

Answer:

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