Wave Motion 5 Question 26

26. A train approaching a hill at a speed of 40km/h sounds a whistle of frequency 580Hz when it is at a distance of 1km from a hill. A wind with a speed of 40km/h is blowing in the direction of motion of the train. Find

(1988,5M)

(a) the frequency of the whistle as heard by an observer on the hill,

(b) the distance from the hill at which the echo from the hill is heard by the driver and its frequency.

(Velocity of sound in air =1200km/h )

Show Answer

Answer:

Correct Answer: 26. (a) 599.33Hz (b) 0.935km,621.43Hz

Solution:

  1. Given vs=vw=40km/h and v=1200km/h= speed of sound.

(a) Frequency observed by observer f=f(v+vwv+vwvs)

Substituting the values, we have

f=580[1200+401200+4040]=599.33Hz

(b) Let x be the distance of the source from the hill at which echo is heard of the sound which was produced when source was at a distance 1km from the hill. Then, time taken by the source to reach from s to s= time taken by the sound to reach from s to hill and then from hill to s. Thus,

1x40=11200+40+x120040

Solving this equation, we get x=0.935km

Frequency heard by the driver of the reflected wave

f=f[vvw+vovvwvs]=580[120040+4012004040]=621.43Hz



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक