SATHEE: Wave Motion 4 Question 8

Wave Motion 4 Question 8

8. A train is moving on a straight track with speed $20 m s^{- 1}$ . It is blowing its whistle at the frequency of $1000 H z$ . The percentage change in the frequency heard by a person standing near the track as the train passes him is close to (speed of sound $= 320 m s^{- 1}$ )

(2015 Main)

(a) $12$

(b) $6$

(d) $24$

Show Answer

Answer:

Correct Answer: 8. (b)

Solution:

Observer is stationary and source is moving.

During approach, $f_{1} = f \frac{v}{v - v_{s}}$

$= 1000 (\frac{320}{320 - 20}) = 1066.67 H z$

During recede, $f_{2} = f (\frac{v}{v + v_{s}})$

$= 1000 (\frac{320}{320 + 20}) = 941.18 H z$

$∣$ change in frequency $∣= (\frac{f_{1} - f_{2}}{f_{1}}) \times 100 \approx 12$

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Wave Motion 4 Question 8

8. A train is moving on a straight track with speed 20ms−1. It is blowing its whistle at the frequency of 1000Hz. The percentage change in the frequency heard by a person standing near the track as the train passes him is close to (speed of sound =320ms−1 )

Answer:

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8. A train is moving on a straight track with speed $20 m s^{- 1}$ . It is blowing its whistle at the frequency of $1000 H z$ . The percentage change in the frequency heard by a person standing near the track as the train passes him is close to (speed of sound $= 320 m s^{- 1}$ )