Wave Motion 4 Question 7

7. A musician produce the sound of second harmonics from open end flute of 50cm. The other person moves toward the musician with speed 10km/h from the second end of room. If the speed of sound 330m/s, the frequency heard by running person will be

(2019 Main, 9 Jan II)

(a) 666Hz

(b) 500Hz

(c) 753Hz

(d) 333Hz

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Solution:

  1. According to the question, the musician uses a open flute of length 50cm and produce second harmonic sound waves

When the flute is open from both ends and produce second harmonic, then

L=λ2f2=vL

where, λ2= wavelength for second harmonic,

f2= frequency for second harmonic 

and v= speed of wave.

For given question f2=vL=33050×102

f2=660Hz (frequency produce by source)

Now, a person runs towards the musician from another end of a hall

vobserver =10km/h (towards source) 

There is apparant change in frequency, which heard by person and given by Doppler’s effect formula

v=f=v[vsound +vobserver vsound ]f=f2[vs+vovsound ]f=660[330+5018330]f=666Hz

Hence, option (a) is correct.



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