SATHEE: Wave Motion 4 Question 22

Wave Motion 4 Question 22

21. A stationary source emits sound of frequency $f_{0} = 492 H z$ . The sound is reflected by a large car approaching the source with a speed of $2 m s^{- 1}$ . The reflected signal is received by the source and superposed with the original. What will be the beat frequency of the resulting signal in Hz? (Given that the speed of sound in air is $330 m s^{- 1}$ and the car reflects the sound at the frequency it has received).

(2017 Adv.)

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Answer:

Correct Answer: 21. (a)

Solution:

Frequency observed at car

$f_{1} = f_{0} (\frac{v + v_{C}}{v}) (v = speed of sound)$

Frequency of reflected sound as observed at the source

$f_{2} = f_{1} (\frac{v}{v - v_{C}}) = f_{0} (\frac{v + v_{C}}{v - v_{C}})$

Beat frequency $= f_{2} - f_{0}$

$\begin{aligned} = f_{0} [\frac{v + v_{C}}{v - v_{C}} - 1] = f_{0} [\frac{2 v_{C}}{v - v_{C}}] \\ = 492 \times \frac{2 \times 2}{328} = 6 H z \end{aligned}$

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Wave Motion 4 Question 22

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