SATHEE: Wave Motion 2 Question 7

Wave Motion 2 Question 7

7. A closed organ pipe has a fundamental frequency of $1.5 k H z$ . The number of overtones that can be distinctly heard by a person with this organ pipe will be (Assume that the highest frequency a person can hear is $20, 000 H z$ )

(a) 7

(b) 4

(d) 6

Show Answer

Answer:

Correct Answer: 7. (d)

Solution:

Fundamental frequency of closed organ pipe is given by $f_{0} = v / 4 L$ , where $v$ is the velocity of sound in it and $L$ is the length of the pipe.

Also, overtone frequencies are given by

$f = (2 n + 1) \frac{v}{4 L} or f = (2 n + 1) f_{0}$

Given that, $f_{0} = 1500 H z$ and $f_{max} = 20000 H z$

This means, $f_{max} > f$

So, $f_{max} > (2 n + 1) f_{0}$

$\Rightarrow 20000 > (2 n + 1) 1500$

$\Rightarrow 2 n + 1 < 13.33 \Rightarrow 2 n < 13.33 - 1$

$\Rightarrow 2 n < 12.33$ or $n < 6.16$

or $n = 6$ (integer number)

Hence, total six overtones will be heard.

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Wave Motion 2 Question 7

7. A closed organ pipe has a fundamental frequency of 1.5kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be (Assume that the highest frequency a person can hear is 20,000Hz )

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

7. A closed organ pipe has a fundamental frequency of $1.5 k H z$ . The number of overtones that can be distinctly heard by a person with this organ pipe will be (Assume that the highest frequency a person can hear is $20, 000 H z$ )