Wave Motion 2 Question 4

4. A wire of length 2L, is made by joining two wires A and B of same length but different radii r and 2r

and made of the same material. It is vibrating at a frequency such that the joint of the two wires forms a node. If the number of antinodes in wire A is p and that in B is q, then the ratio p:q is

(2019 Main, 8 April I)

(a) 3:5

(b) 4:9

(c) 1:2

(d) 1:4

Show Answer

Answer:

Correct Answer: 4. (c)

Solution:

Let mass per unit length of wires are μA and μB, respectively.

For same material, density is also same.

So, μA=ρπr2LL=μ and μB=ρ4πr2LL=4μ

Tension (T) in both connected wires are same.

So, speed of wave in wires are

vA=TμA=Tμ[μA=μ and μB=4μ]vB=TμB=T4μ

So, nth harmonic in such wires system is

fnth=pv2LfA=pvA2L=p2LTμ

(for p antinodes)

Similarly, fB=qvB2L=q2LT4μ=12(q2LTμ)

 (for q antinodes) 

As frequencies fA and fB are given equal.

So, fA=fBp2LTμ=q2[12LTμ]

pq=12p:q=1:2



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक