Wave Motion 2 Question 38

38. Sound waves of frequency 660Hz fall normally on a perfectly reflecting wall. The shortest distance from the wall at which the air particles have maximum amplitude of vibration is ….. m. Speed of sound =330m/s.

(1984, 2M)

Integer Answer Type Questions

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Answer:

Correct Answer: 38. 0.125

Solution:

  1. Wall will be a node (displacement). Therefore, shortest distance from the wall at which air particles have maximum amplitude of vibration (displacement antinode) should be λ/4. Here, λ=vf=330660=0.5m

Desired distance is 0.54=0.125m



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