SATHEE: Wave Motion 1 Question 16

Wave Motion 1 Question 16

16. A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of $3 m / s$ and $90 m / s^{2}$ respectively. Velocity of the wave is $20 m / s$ . Find the waveform.

(2005, 2M)

Show Answer

Solution:

Maximum particle velocity,

$ω A = 3 m / s$

Maximum particle acceleration,

$ω^{2} A = 90 m / s^{2}$

Velocity of wave, $\frac{ω}{k} = 20 m / s$

From Eqs. (i), (ii) and (iii), we get

$ω = 30 r a d / s \Rightarrow A = 0.1 m and k = 1.5 m^{- 1}$

$∴$ Equation of waveform should be

$\begin{aligned} y = A \sin (ω t + k x + ϕ) \\ y = (0.1 m) \sin [(30 r a d / s) t \pm (1.5 m^{- 1}) x + ϕ] \end{aligned}$

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Wave Motion 1 Question 16

16. A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of 3m/s and 90m/s2 respectively. Velocity of the wave is 20m/s. Find the waveform.

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

16. A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of $3 m / s$ and $90 m / s^{2}$ respectively. Velocity of the wave is $20 m / s$ . Find the waveform.