Wave Motion 1 Question 16
16. A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of $3 m / s$ and $90 m / s^{2}$ respectively. Velocity of the wave is $20 m / s$. Find the waveform.
(2005, 2M)
Show Answer
Solution:
- Maximum particle velocity,
$$ \omega A=3 m / s $$
Maximum particle acceleration,
$$ \omega^{2} A=90 m / s^{2} $$
Velocity of wave, $\frac{\omega}{k}=20 m / s$
From Eqs. (i), (ii) and (iii), we get
$$ \omega=30 rad / s \Rightarrow A=0.1 m \quad \text { and } \quad k=1.5 m^{-1} $$
$\therefore$ Equation of waveform should be
$$ \begin{aligned} & y=A \sin (\omega t+k x+\phi) \\ & y=(0.1 m) \sin \left[(30 rad / s) t \pm\left(1.5 m^{-1}\right) x+\phi\right] \end{aligned} $$
