Simple Harmonic Motion 5 Question 6

11. A particle executes simple harmonic motion between x=A and x=+A. The time taken for it to go from O to A/2 is T1 and to go from A/2 to A is T2, then

(2001, 2M)

(a) T1<T2

(b) T1>T2

(c) T1=T2

(d) T1=2T2

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Answer:

Correct Answer: 11. (a)

Solution:

  1. In SHM, velocity of particle also oscillates simple harmonically. Speed is more near the mean position and less near the extreme positions. Therefore, the time taken for the particle to go from O to A/2 will be less than the time taken to go it from A/2 to A, or T1<T2.

NOTE

From the equations of SHM we can show that

 So, that t1+t2=TOA=T/4

t1=T0A/2=T/12 and t2=TA/2A=T/6



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