Simple Harmonic Motion 5 Question 18

23. Function x=Asin2ωt+Bcos2ωt+Csinωtcosωt represents SHM

(a) For any value of A,B and C (except C=0 )

(2006,5M)]

(b) If A=B,C=2B, amplitude =|B2|

(c) If A=B;C=0

(d) If A=B;C=2B, amplitude =|B|

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Answer:

Correct Answer: 23. (a) θ=tan115

(b) 2πR6.11

Solution:

  1. For A=B and C=2B

X=Bcos2ωt+Bsin2ωt=2Bsin2ωt+π4

This is equation of SHM of amplitude 2B.

If A=B and C=2B, then X=B+Bsin2ωt

This is also equation of SHM about the point X=B. Function oscillates between X=0 and X=2B with amplitude B.



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