Rotation 2 Question 13

13. A particle of mass m is projected with a velocity v making an angle of 45 with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height h is

(a) zero

(b) mv3/(42g)

(c) mv3/(2g)

(d) m2gh3

(1990, 2M)

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Answer:

Correct Answer: 13. (b)

Solution:

  1. L=mv2r

Here, r=h=v2sin2452g=v24g

L=mv2v24g=mv342g



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