Rotation 1 Question 14

17. From a circular disc of radius R and mass 9M, a small disc of radius R/3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is

(2005)

(a) 4MR2

(b) 409MR2

(c) 10MR2

(d) 379MR2

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Answer:

Correct Answer: 17. (a)

Solution:

  1. Iremaining =Iwhole Iremoved 

or I=12(9M)(R)212mR32+12m2R32

Here, m=9MπR2×πR32=M

Substituting in Eq. (i), we have

I=4MR2



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