SATHEE: Properties of Matter 1 Question 2

Properties of Matter 1 Question 2

2. The elastic limit of brass is $379 M P a$ . What should be the minimum diameter of a brass rod, if it is to support a $400 N$ load without exceeding its elastic limit?

(2019 Main, 10 April II)

(a) $0.90 m m$

(b) $1.00 m m$

(d) $1.36 m m$

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Answer:

Correct Answer: 2. (c)

Solution:

Let $d_{min} =$ minimum diameter of brass.

Then, stress in brass rod is given by

$σ = \frac{F}{A} = \frac{4 F}{π d_{min}^{2}} [∵ A = \frac{π d^{2}}{4}]$

For stress not to exceed elastic limit, we have

$σ \leq 379 M P a$

$\Rightarrow \frac{4 F}{π d^{2} min} \leq 379 \times 10^{6}$

Here,

$F = 400 N$

$∴ d_{min}^{2} = \frac{1600}{π \times 379 \times 10^{6}}$

$\Rightarrow d_{min} = 1.16 \times 10^{- 3} m = 1.16 m m$

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Properties of Matter 1 Question 2

2. The elastic limit of brass is $379 M P a$ . What should be the minimum diameter of a brass rod, if it is to support a $400 N$ load without exceeding its elastic limit?

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Properties of Matter 1 Question 2

2. The elastic limit of brass is 379MPa. What should be the minimum diameter of a brass rod, if it is to support a 400N load without exceeding its elastic limit?

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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2. The elastic limit of brass is $379 M P a$ . What should be the minimum diameter of a brass rod, if it is to support a $400 N$ load without exceeding its elastic limit?