Optics 6 Question 9

10. The resolving power of electron microscope is higher than that of an optical microscope because the wavelength of electrons is than the wavelength of visible light.

(1992, 1M)

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Solution:

  1. In Young’s double slit experiment, the condition of bright fringe and dark fringe are,

for bright fringes (maxima), path difference =nλ

dsinθ=nλ

for dark fringes (minima),

path-difference =(2n1)λ2

dsinθ=(2n1)λ2

For the given question, distance between slits

$$

(d)=0.320 mm $$

Wavelength of light used (λ)=500nm

Angular range for bright fringe (θ)=30 to 30

Hence, for bright-fringe,

nλ=dsinθn=dsinθλ=0.320×103×sin30500×109nmax=320

Total number of maxima between the two lines are

Here, n=(nmax×2)+1 nn=(320×2)+1 n=641



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