Optics 6 Question 19

21. In a YDSE bi-chromatic light of wavelengths 400nm and 560nm are used. The distance between the slits is 0.1mm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is

(2004, 2M)

(a) 4mm

(b) 5.6mm

(c) 14mm

(d) 28mm

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Solution:

  1. Let nth minima of 400nm coincides with m th minima of 560nm, then

(2n1)4002=(2m1)5602 or 2n12m1=75=1410=

i.e. 4th minima of 400nm coincides with 3rd minima of 560nm.

Location of this minima is,

Y1=(2×41)(1000)(400×106)2×0.1=14mm

Next 11th minima of 400nm will coincide with 8th minima of 560nm.

Location of this minima is,

Y2=(2×111)(1000)(400×106)2×0.1=42mm

Required distance =Y2Y1=28mm



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