Optics 6 Question 14

16. In the Young’s double slit experiment using a monochromatic light of wavelength λ the path difference (in terms of an integer n ) corresponding to any point having half the peak intensity is

(a) (2n+1)λ2

(b) (2n+1)λ4

(c) (2n+1)λ8

(d) (2n+1)λ16

(2013 Adv.)

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Solution:

I=Imaxcos2φ2I=Imax2

Given,

From Eqs. (i) and (ii), we have

φ=π2,3π2,5π2

Or path difference, Δx=λ2πφ

Δx=λ4,3λ4,5λ4..,2n+14λ



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