SATHEE: Modern Physics 7 Question 72

Modern Physics 7 Question 72

2. In an amplitude modulator circuit, the carrier wave is given by $C (t) = 4 \sin (20000 π t)$ while modulating signal is given by, $m (t) = 2 \sin (2000 π t)$ . The values of modulation index and lower side band frequency are

(Main 2019, 12 April II)

(a) 0.5 and $10 k H z$

(b) 0.4 and $10 k H z$

(d) 0.5 and $9 k H z$

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Solution:

Given, carrier wave,

$C (t) = 4 \sin (20000 π t)$

Modulating signal,

$m (t) = 2 \sin (2000 π t)$

So, carrier wave’s amplitude and frequency are

$\begin{aligned} A_{c} = 4 V, ω_{c} = 20000 π = 2 π \times 10^{4} r a d / s \\ \Rightarrow & f_{c} = \frac{ω_{c}}{2 π} = 10^{4} H z = 10 k H z \end{aligned}$

and modulating signal’s amplitude and frequency are

$A_{m} = 2 V, ω_{m} = 2000 π = 2 π \times 10^{3} r a d / s$

$\Rightarrow f_{m} = \frac{ω_{m}}{2 π} = 10^{3} H z = 1 k H z$

So, modulating index is $m = \frac{A_{m}}{A_{c}} = \frac{2}{4} = 0.5$

and lower side band frequency is,

$f_{L S B} = f_{c} - f_{m} = 10 - 1 = 9 k H z$

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Modern Physics 7 Question 72

2. In an amplitude modulator circuit, the carrier wave is given by $C (t) = 4 \sin (20000 π t)$ while modulating signal is given by, $m (t) = 2 \sin (2000 π t)$ . The values of modulation index and lower side band frequency are

Solution:

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Modern Physics 7 Question 72

2. In an amplitude modulator circuit, the carrier wave is given by C(t)=4sin⁡(20000πt) while modulating signal is given by, m(t)=2sin⁡(2000πt). The values of modulation index and lower side band frequency are

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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2. In an amplitude modulator circuit, the carrier wave is given by $C (t) = 4 \sin (20000 π t)$ while modulating signal is given by, $m (t) = 2 \sin (2000 π t)$ . The values of modulation index and lower side band frequency are