SATHEE: Modern Physics 7 Question 25

Modern Physics 7 Question 25

26. A TV transmission tower has a height of $140 m$ and the height of the receiving antenna is $40 m$ . What is the maximum distance upto which signals can be broadcasted from this tower in LOS (Line of Sight) mode? (Take, radius of earth $= 6.4 \times 10^{6} m$ ).

(Main 2019, 10 Jan I)

(a) $65 k m$

(b) $80 k m$

(c) $40 k m$

(d) $48 k m$

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Solution:

Maximum distance of transmission is given by

$d = \sqrt{2 R h_{T}} + \sqrt{2 R h_{R}}$

where, $h_{T} =$ height of transmitter, $= 140 m$ ,

$h_{R} = height of receiver = 40 m and$

$R = radius of earth = 6.4 \times 10^{6} m$

Substituting values, we get

$d = \sqrt{2 \times 6.4 \times 10^{6}} (\sqrt{140} + \sqrt{40}) = 65 k m$

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Modern Physics 7 Question 25

26. A TV transmission tower has a height of 140m and the height of the receiving antenna is 40m. What is the maximum distance upto which signals can be broadcasted from this tower in LOS (Line of Sight) mode? (Take, radius of earth =6.4×106m ).

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26. A TV transmission tower has a height of $140 m$ and the height of the receiving antenna is $40 m$ . What is the maximum distance upto which signals can be broadcasted from this tower in LOS (Line of Sight) mode? (Take, radius of earth $= 6.4 \times 10^{6} m$ ).