Modern Physics 7 Question 21

22. An electromagnetic wave of intensity 50Wm2 enters in a medium of refractive index ’ n ’ without any loss. The ratio of the magnitudes of electric fields and the ratio of the magnitudes of magnetic fields of the wave before and after entering into the medium are respectively, given by

(a) 1n,n

(b) (n,n)

(c) 1n,1n

(d) n,1n

(Main 2019, 11 Jan I)

Show Answer

Solution:

  1. In the free space, the speed of electromagnetic wave is given as,

c=1μ0ε0=E0B0

where, E0 and B0 are the amplitudes of varying electric and magnetic fields, respectively.

Now, when it enters in a medium of refractive index ’ n ‘, its speed is given as,

v=1με=1Kε0μ=EB

where, K is dielectric strength of the medium.

Using Eqs. (i) and (ii), we get

vc=1K

( For a transparent medium, μ0μ)

Also, refractive index of medium is ’ n ’ and is given as

cv=n or vc=1n

From Eqs. (iii) and (iv), we get

n=K or K=n2

The intensity of a EM wave is given as,

I=12ε0E02c

and in the medium, it is given as I=12Kε0E2v

It is given that, I=I

12ε0E02c=12Kε0E2v or E0E2=Kvc

From Eqs. (iv), (v) and (vi), we get

E0E2=n2n=n or E0/E=n

Similarly, 12B02μ0c=12B2μ0vB0B=1n

Alternate method

We know that,

E0B0=c air/vacuum EB medium =v

 Also, n=cvE0/B0E/B=cv=nE0/EB0/B=n

This is possible only if E0E=n and B0B=1n.



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक