Modern Physics 6 Question 2

2. The transfer characteristic curve of a transistor, having input and output resistance 100Ω and 100kΩ respectively, is shown in the figure. The voltage and power gain, are respectively,

(Main 2019, 12 April I)

(a) 2.5×104,2.5×106

(b) 5×104,5×106

(c) 5×104,5×105

(d) 5×104,2.5×106

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Solution:

  1. Given curve is between Ic and Ib as output and input currents, respectively

So, it is transfer characteristics curve of a common emitter (CE) configuration.

In CE configuration,

Current gain, β=Iout Iin =IcIb

Voltage gain,

AV=Vout Vin =Ic×Rout Ib×Rin =β×Rout Rin 

and power gain

AP=Pout Pin =Ic2×Rout Ib2×Rin =β2×Rout Rin 

Given, Rin =100Ω and Rout =100×103Ω

From Eq. (i), we get

β=5mA100μA or 10mA200μA or 15mA300μA or 20mA400μAβ=5×103100×106=50 (iv) 

From Eqs. (ii) and (iv), we get

Voltage gain, AV=β×Rout Rin =50×100×103100

AV=50000=5×104

From Eqs. (iii) and (iv), we get

Power gain, AP=β2×Rout Rin 

=(50)2×100×103100=2500×1000AP=2.5×106



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