Modern Physics 5 Question 5

5. Consider the nuclear fission

Ne202He4+C12

Given that the binding energy/nucleon of Ne20,He4 and C12 are respectively, 8.03MeV,7.07MeV and 7.86MeV, identify the correct statement.

(Main 2019, 10 Jan II)

(a) Energy of 3.6MeV will be released.

(b) Energy of 12.4MeV will be supplied.

(c) 8.3MeV energy will be released.

(d) Energy of 11.9MeV has to be supplied.

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Answer:

Correct Answer: 5. (*)

Solution:

  1. Energy absorbed or released in a nuclear reaction is given by

ΔQ= Binding energy of products

-Binding energy of reactants.

If energy is absorbed, ΔQ is negative and if it is positive then energy is released. Also, Binding energy = Binding energy per nucleon × Number of nucleons.

Here, binding energy of products

=2×( B.E. of He4)+( B.E. of C12)=2(4×7.07)+(12×7.86)=150.88MeV

and binding energy of reactants =20×8.03=160.6MeV

So, ΔQ=( B.E. )Products ( B.E. )reactants  =150.88160.6=9.72MeV

As ΔQ is negative

energy of 9.72Mev is absorbed in the reaction.

No option is correct



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