Modern Physics 5 Question 29

32. The isotopes 512 B having a mass 12.014u undergoes β-decay to 612C.612Chas an excited state of the nucleus (612C) at 4.041 MeV above its ground state. If 512B decays to 512C, the maximum kinetic energy of the β-particle in units of MeV is ( 1u=931.5MeV/c2, where c is the speed of light in vacuum)

(2016 Adv.)

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Solution:

  1. 512B613C+10e+ν¯

Mass of 612C=12.000u (by definition of 1 a.m.u.)

Q-value of reaction,

Q=(MBMC)×c2=(12.01412.000)×931.5=13.041MeV4.041MeV of energy is taken by 6512C Maximum KE of β-particle is (13.0414.041)=9MeV



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