SATHEE: Modern Physics 4 Question 27

Modern Physics 4 Question 27

28. The wavelength of $K_{α}, X$ -rays produced by an X-ray tube is $0.76 \AA$ . The atomic number of the anode material of the tube is

(1996, 2M)

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Solution:

$\frac{1}{λ_{K_{α}}} = R (Z - 1)^{2} \frac{1}{1^{2}} - \frac{1}{2^{2}} = \frac{3}{4} R (Z - 1)^{2}$

$∴ (Z - 1) = \frac{2}{\sqrt{3 R λ_{K_{α}}}}$

Here, $R =$ Rydberg’s constant

$= 1.097 \times 10^{7} m^{- 1} and$

$λ_{K_{α}} = 0.76 \AA = 0.76 \times 10^{- 10} m$

Substituting the values, we have

$or Z = 39$

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Modern Physics 4 Question 27

28. The wavelength of Kα,X-rays produced by an X-ray tube is 0.76\AA. The atomic number of the anode material of the tube is

Solution:

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28. The wavelength of $K_{α}, X$ -rays produced by an X-ray tube is $0.76 \AA$ . The atomic number of the anode material of the tube is