Modern Physics 4 Question 20

20. The KαX-ray emission line of tungsten occurs at λ=0.021nm. The energy difference between K and L levels in this atoms is about

(1997C, 1M)

(a) 0.51MeV

(b) 1.2MeV (c) 59keV

(d) 13.6eV

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Solution:

  1. λkα=0.021nm=0.21\AA

Since, λkα corresponds to the transition of an electron from L-shell to K-shell, therefore

ELEK=( in eV )=12375λ( in \AA)=123750.2158928eV

or

ΔE59keV



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