Modern Physics 4 Question 15

15. The potential difference applied to an X-ray tube is 5kV and the current through it is 3.2mA. Then the number of electrons striking the target per second is

(2002,2M)

(a) 2×1016

(b) 5×106

(c) 1×1017

(d) 4×1015

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Solution:

i=qt=netn=ite

Substituting i=3.2×103A,

e=1.6×1019C and t=1s we get, n=2×1016



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