Modern Physics 3 Question 12

12. The half-life of 215At is 100μ s. The time taken for the activity

of a sample of 215 At to decay to 116 th of its initial value is (2002,2M)

(a) 400μs

(b) 63μs

(c) 40μs

(d) 300μs

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Solution:

R=R012n

Here R = activity of radioactive substance after n half-lives

=R016

Substituting in Eq. (i), we get n=4

t=(n)t1/2=(4)(100μs)=400μs



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