Modern Physics 3 Question 1

1. In a radioactive decay chain, the initial nucleus is 90232Th. At the end, there are 6α-particles and 4β-particles which are emitted. If the end nucleus is ZAX,A and Z are given by

(a) A=202;Z=80

(b) A=208;Z=82

(c) A=200;Z=81

(d) A=208;Z=80

(Main 2019, 12 Jan II)

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Solution:

  1. An α-particle decay (24He) reduces, mass number by 4 and atomic number by 2 .

Decay of 6α-particles results

90232Th6α901223224Y=78208Y

A β-decay does not produces any change in mass number but it increases atomic number by 1 .

Decay of 4β-particles results

78208Y4β82208X

In the end nucleus A=208,Z=82



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