Modern Physics 2 Question 7
7. A metal plate of area is illuminated by a radiation of intensity . The work function of the metal is . The energy of the incident photons is and only of it produces photoelectrons. The number of emitted photoelectrons per second and their maximum energy, respectively will be (Take,
(a)
(b)
(c)
(d)
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Solution:
- We know that, intensity of a radiation
with energy ’ ’ incident on a plate per second per unit area is given as
i.e., energy incident per unit time
Substituting the given values, we get
Using Einstein’s photoelectric equation, we can find kinetic energy of the incident radiation as
Now, energy per unit time for incident photons will be
From Eqs. (i) and (iii), we get
So, emitted electrons per second are