Modern Physics 1 Question 33

30. If the mass of the particle is m=1.0×1030kg and a=6.6nm, the energy of the particle in its ground state is closest to

(2009)

(a) 0.8meV

(b) 8meV

(c) 80meV

(d) 800meV

Show Answer

Solution:

  1. From Eq. (i) E=n2h28a2m

In ground state n=1

E1=h28ma2

Substituting the values, we get

E1=8meV



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