SATHEE: Magnetics 4 Question 10

Magnetics 4 Question 10

11. A conducting circular loop of radius $r$ carries a constant current $i$ . It is placed in a uniform magnetic field $B_{0}$ such that $B_{0}$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

(1983, 1M)

(a) $ir B_{0}$

(b) $2 π i r B_{0}$

(d) $π ir B_{0}$

Passage Based Questions

Passage

The figure shows a circular loop of radius $a$ with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is $d$ . The loop and the wires are carrying the same current $I$ . The current in the loop is in the counter-clockwise direction if seen from above.

(2014 Adv.)

Show Answer

Answer:

Correct Answer: 11. (c)

Solution:

Magnetic force on a current carrying loop in uniform magnetic field is zero.

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Magnetics 4 Question 10

11. A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B0 such that B0 is perpendicular to the plane of the loop. The magnetic force acting on the loop is

Passage Based Questions

Passage

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

11. A conducting circular loop of radius $r$ carries a constant current $i$ . It is placed in a uniform magnetic field $B_{0}$ such that $B_{0}$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is