SATHEE: Magnetics 1 Question 22

Magnetics 1 Question 22

22. $H^{+}, H e^{+}$ and $O^{2 +}$ all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity. The masses of $H^{+}, H e^{+}$ and $O^{2 +}$ are $1 a m u, 4 a m u$ and $16 a m u$ respectively. Then

(a) $H^{+}$ will be deflected most

$(1994, 2 M)$

(b) $O^{2 +}$ will be deflected most

(d) all will be deflected equally

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Answer:

Correct Answer: 22. (a, c)

Solution:

$r = \frac{m v}{B q} = \frac{p}{B q} = \frac{\sqrt{2 K m}}{B q} i.e. r \propto \frac{\sqrt{m}}{q}$

If $K$ and $B$ are same. i.e., $r_{H^{+}} : r_{H e^{+}} : r_{O^{2 +}} = \frac{\sqrt{1}}{1} : \frac{\sqrt{4}}{1} : \frac{\sqrt{16}}{2} = 1 : 2 : 2$

Therefore, $H e^{+}$ and $O^{2 +}$ will be deflected equally but $H^{+}$ having the least radius will be deflected most.

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Magnetics 1 Question 22

22. H+,He+and O2+ all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity. The masses of H+,He+and O2+ are 1amu,4amu and 16amu respectively. Then

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22. $H^{+}, H e^{+}$ and $O^{2 +}$ all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity. The masses of $H^{+}, H e^{+}$ and $O^{2 +}$ are $1 a m u, 4 a m u$ and $16 a m u$ respectively. Then