Laws of Motion 5 Question 5

5. System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2m and m just after the string is cut will be

(2006, 3M)

(a) g/2 upwards, g downwards

(b) g upwards, g/2 downwards

(c) g upwards, 2g downwards

(d) 2g upwards, g downwards

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Answer:

Correct Answer: 5. (c)

Solution:

  1. Initially under equilibrium of mass m

T=mg

Now, the string is cut. Therefore, T=mg force is decreased on mass m upwards and downwards on mass 2m.

am=mgm=g (downwards)  and a2m=mg2m=g2 (upwards) 



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