Laws of Motion 3 Question 25

27. A block is moving on an inclined plane making an angle 45 with the horizontal and the coefficient of friction is μ.

The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down.If we define N=10μ, then N is

(2011)

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Answer:

Correct Answer: 27. 5

Solution:

F1=mgsinθ+μmgcosθ

F2=mgsinθμmgcosθ Given that F1=3F2 or (sin45+μcos45)=3(sin45μcos45)

On solving, we get μ=0.5N=10μ=5



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