Laws of Motion 3 Question 2

2. A block kept on a rough inclined plane, as shown in the figure, remains at rest upto a maximum force 2N down the inclined plane. The maximum external force up the inclined plane that

does not move the block is 10N.

The coefficient of static friction between the block and the plane is

(2019 Main, 12 Jan I)

(Take, g=10m/s2 )

(a) 23

(b) 32

(c) 34

(d) 12

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Answer:

Correct Answer: 2. (b)

Solution:

  1. Block does not move upto a maximum applied force of 2N down the inclined plane.

So, equating forces, we have;

2+mgsinθ=f

or 2+mgsinθ=μmgcosθ

Similarly, block also does not move upto a maximum applied force of 10N up the plane.

Now, equating forces, we have

mgsinθ+f=10N

or mgsinθ+μmgcosθ=10

Now, solving Eqs. (i) and (ii), we get

mgsinθ=4

and μmgcosθ=6

Dividing, Eqs. (iii) and (iv), we get

μcotθ=32μ=3tanθ2=3tan302μ=32



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