SATHEE: Laws of Motion 3 Question 14

Laws of Motion 3 Question 14

15. A small block of mass of $0.1 k g$ lies on a fixed inclined plane $P Q$ which makes an angle $θ$ with the horizontal. A horizontal force of $1 N$ acts on the block through its centre of mass as shown in the

figure. The block remains stationary if (take $g = 10 m / s^{2}$ )

(a) $θ = 45^{\circ}$ .

(2012)

(b) $θ > 45^{\circ}$ and a frictional force acts on the block towards $P$

(d) $θ < 45^{\circ}$ and a frictional force acts on the block towards $Q$

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Answer:

Correct Answer: 15. (a, c)

Solution:

$w = m g = 0.1 \times 10 = 1 N$

$F_{1} =$ component of weight $= 1 \cdot \sin θ = \sin θ$ $F_{2} =$ component of applied force $= 1 \cdot \cos θ = \cos θ$

Now, at $θ = 45^{\circ} : F_{1} = F_{2}$ and block remains stationary without the help of friction.

For $θ > 45^{\circ}, F_{1} > F_{2}$ , so friction will act towards $Q$ .

For $θ < 45^{\circ}, F_{2} > F_{1}$ and friction will act towards $P$ .

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Laws of Motion 3 Question 14

15. A small block of mass of $0.1 k g$ lies on a fixed inclined plane $P Q$ which makes an angle $θ$ with the horizontal. A horizontal force of $1 N$ acts on the block through its centre of mass as shown in the

Fill in the Blank

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws of Motion 3 Question 14

15. A small block of mass of 0.1kg lies on a fixed inclined plane PQ which makes an angle θ with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in the

Fill in the Blank

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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15. A small block of mass of $0.1 k g$ lies on a fixed inclined plane $P Q$ which makes an angle $θ$ with the horizontal. A horizontal force of $1 N$ acts on the block through its centre of mass as shown in the