SATHEE: Laws of Motion 2 Question 2

Laws of Motion 2 Question 2

2. A mass of $10 k g$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the mass, the rope deviated at an angle of $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (Take, $g = 10 m s^{- 2}$ )

(2019 Main, 9 Jan II)

(a) $70 N$

(b) $200 N$

(d) $140 N$

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Answer:

Correct Answer: 2. (d)

Solution:

FBD of the given system is follow

Let $T =$ tension in the rope.

For equilibrium condition of the mass,

$\begin{array}{lr} Σ F_{x} = 0 & (force in x -direction) \\ Σ F_{y} = 0 & ( force in y -direction) \end{array}$

When $Σ F_{x} = 0$ , then

$∵ F = T \sin 45^{\circ}$

When $Σ F_{y} = 0$ , then

$M g = T \cos 45^{\circ}$

Using Eqs. (i) and (ii),

$\begin{aligned} \Rightarrow \frac{F}{M g} = \frac{T \sin 45^{\circ}}{T \cos 45^{\circ}} \Rightarrow \frac{F}{M g} = \frac{\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt{2}}} = 1 \\ \Rightarrow F = M g = 10 \times 10 = 100 N \end{aligned}$

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Laws of Motion 2 Question 2

2. A mass of $10 k g$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the mass, the rope deviated at an angle of $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (Take, $g = 10 m s^{- 2}$ )

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws of Motion 2 Question 2

2. A mass of 10kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the mass, the rope deviated at an angle of 45∘ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (Take, g=10ms−2 )

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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2. A mass of $10 k g$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the mass, the rope deviated at an angle of $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (Take, $g = 10 m s^{- 2}$ )