SATHEE: Laws of Motion 1 Question 4

Laws of Motion 1 Question 4

4. The pulley arrangements of figures (a) and (b) are identical. The mass of the rope is negligible. In Fig. (a), the mass $m$ is

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Answer:

Correct Answer: 4. $F$

Solution:

In these cases, $a = \frac{Net pulling force}{Total mass}$

Net pulling force in both the cases is

$2 m g - m g = m g$

But mass (to be pulled) in case (a) is $3 m$ and in case (b) is $m$ .

$\begin{array}{lll} Therefore, & a_{1} = \frac{m g}{3 m} = \frac{g}{3} & [in case (a)] \\ and & a_{2} = \frac{m g}{m} = g & [in case \\ or & a_{1} < a_{2} \end{array}$

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Laws of Motion 1 Question 4

4. The pulley arrangements of figures (a) and (b) are identical. The mass of the rope is negligible. In Fig. (a), the mass $m$ is

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Laws of Motion 1 Question 4

4. The pulley arrangements of figures (a) and (b) are identical. The mass of the rope is negligible. In Fig. (a), the mass m is

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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4. The pulley arrangements of figures (a) and (b) are identical. The mass of the rope is negligible. In Fig. (a), the mass $m$ is