Kinematics 5 Question 7

9. A projectile is given an initial velocity of (i+2j)m/s, where, i is along the ground and j is along the vertical. If g=10m/s2, then the equation of its trajectory is

(2013 Main)

(a) y=x5x2

(b) y=2x5x2

(c) 4y=2x5x2

(d) 4y=2x25x2

Fill in the Blank

Show Answer

Answer:

Correct Answer: 9. (b)

Solution:

  1. Initial velocity =(i+2j)m/s

Magnitude of initial velocity, u=(1)2+(2)2=5m/s

Equation of trajectory of projectile is

y=xtanθgx22u2(1+tan2θ)tanθ=yx=21=2y=x×210(x)22(5)2[1+(2)2]=2x10(x2)2×5(1+4)=2x5x2



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक