Kinematics 5 Question 11
1. Two particles are projected from the same point with the same speed
(12 April 2019 Shift II)
(a)
(b)
(c)
(d)
Show Answer
Answer:
Correct Answer: 1. (b)
Solution:
1.15+\frac{1}{2} a t^{2} & =\left(u \cos 60^{\circ}\right) t \ \therefore \quad 1.15+\frac{1}{2} a(\sqrt{3})^{2} & =10 \times \frac{1}{2} \times \sqrt{3} \end{aligned} $$
Solving this equation, we get
