Kinematics 4 Question 7

7. A particle starts from rest. Its acceleration (a) versus time ( $t$ ) is as shown in the figure. The maximum speed of the particle will be

(2004, 2M)

(a) $110 m / s$

(b) $55 m / s$

(c) $550 m / s$

(d) $660 m / s$

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Solution:

  1. Area under acceleration-time graph gives the change in velocity.

Hence, $\quad v _{\max }=1 / 2 \times 10 \times 11=55 m / s$



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