SATHEE: Kinematics 2 Question 7

Kinematics 2 Question 7

9. A rocket is moving in a gravity free space with a constant acceleration of $2 m s^{- 2}$ along $+ x$ direction (see

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Answer:

Correct Answer: 9. $(2$ or 8 $)$

Solution:

Motion of ball $A$ relative to rocket.

Consider motion of two balls with respect to rocket.

Maximum distance of ball $A$ from left wall

$= \frac{u^{2}}{2 a} = \frac{0.3 \times 0.3}{2 \times 2} = \frac{0.09}{4} \approx 0.02 m (as 0 = u^{2} - 2 a S)$

So, collision of two balls will take place very near to left wall.

Motion of ball $B$ relative to rocket

For $B S = u t + \frac{1}{2} a t^{2} \Rightarrow - 4 = - 0.2 t - \frac{1}{2} 2 t^{2}$

Solving this equation, we get,

$t = 1.9 s$

$∴$ Nearest Integer $= 2 s$

Alternate

$\begin{aligned} S_{1} = 0.2 t + \frac{1}{2} \times 2 \times t^{2} \Rightarrow S_{2} = 0.3 t - \frac{1}{2} \times 2 \times t^{2} \\ S_{1} + S_{2} = 4 \Rightarrow 0.5 t = 4 \\ t = 8 s \end{aligned}$

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Kinematics 2 Question 7

9. A rocket is moving in a gravity free space with a constant acceleration of $2 m s^{- 2}$ along $+ x$ direction (see

Answer:

Alternate

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Kinematics 2 Question 7

9. A rocket is moving in a gravity free space with a constant acceleration of 2ms−2 along +x direction (see

Answer:

Alternate

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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9. A rocket is moving in a gravity free space with a constant acceleration of $2 m s^{- 2}$ along $+ x$ direction (see