Heat and Thermodynamics 4 Question 40

42. The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressure p1 and p2 are as shown in figure. It follows from the graphs that p1 is greater than p2.(1982,2M)

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Solution:

pV=nRT

V=(nRp)T

Comparing this with y=mx,VT graph is a straight line passing through origin with slope =nRp.

 or  slope 1p( slope )1>( slope )2p1<p2 43. vrms =3RTM

It not only depends on T but also on M.



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