SATHEE: Heat and Thermodynamics 4 Question 26

Heat and Thermodynamics 4 Question 26

28. The average translational energy and the rms speed of molecules in a sample of oxygen gas at $300 K$ are $6.21 \times 10^{- 21} J$ and $484 m / s$ respectively. The corresponding values at $600 K$ are nearly (assuming ideal gas behaviour)

(1997, 1M)

(a) $12.42 \times 10^{- 21} J, 968 m / s$

(b) $8.78 \times 10^{- 21} J, 684 m / s$

(d) $12.42 \times 10^{- 21} J, 684 m / s$

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Solution:

The average translational $K E = \frac{3}{2} k T$ which is directly proportional to $T$ , while rms speed of molecules is given by

$v_{r m s} = \sqrt{\frac{3 R T}{M}} i.e. v_{r m s} \propto \sqrt{T}$

When temperature of gas is increased from $300 K$ to $600 K$ (i.e. 2 times), the average translational $K E$ will increase to 2 times and rms speed to $\sqrt{2}$ or 1.414 times.

$∴$ Average translational KE $= 2 \times 6.21 \times 10^{- 21} J$

and

$= 12.42 \times 10^{- 21} J$

$\begin{aligned} v_{r m s} & = (1.414) (484) m / s \\ \approx 684 m / s \end{aligned}$

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Heat and Thermodynamics 4 Question 26

28. The average translational energy and the rms speed of molecules in a sample of oxygen gas at $300 K$ are $6.21 \times 10^{- 21} J$ and $484 m / s$ respectively. The corresponding values at $600 K$ are nearly (assuming ideal gas behaviour)

Solution:

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Heat and Thermodynamics 4 Question 26

28. The average translational energy and the rms speed of molecules in a sample of oxygen gas at 300K are 6.21×10−21J and 484m/s respectively. The corresponding values at 600K are nearly (assuming ideal gas behaviour)

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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28. The average translational energy and the rms speed of molecules in a sample of oxygen gas at $300 K$ are $6.21 \times 10^{- 21} J$ and $484 m / s$ respectively. The corresponding values at $600 K$ are nearly (assuming ideal gas behaviour)