SATHEE: Heat and Thermodynamics 1 Question 3

Heat and Thermodynamics 1 Question 3

3. When $100 g$ of a liquid $A$ at $100^{\circ} C$ is added to $50 g$ of a liquid $B$ at temperature $75^{\circ} C$ , the temperature of the mixture becomes $90^{\circ} C$ . The temperature of the mixture, if $100 g$ of liquid $A$ at $100^{\circ} C$ is added to $50 g$ of liquid $B$ at $50^{\circ} C$ will be

(a) $60^{\circ} C$

(b) $80^{\circ} C$

(d) $85^{\circ} C$

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Solution:

In first case according to principle of calorimetry, heat lost by liquid $A =$ heat gained by liquid $B$

$m_{A} S_{A} Δ T_{A} = m_{B} S_{B} Δ T_{B}$

where, $S_{A}$ is specific heat capacity of $A$ and $S_{B}$ is specific heat capacity of $B$

$\begin{aligned} \Rightarrow 100 \times S_{A} (100 - 90) = 50 \times S_{B} (90 - 75) \\ \Rightarrow 1000 S_{A} = 50 \times 15 S_{B} \\ or 4 S_{A} = 3 S_{B} \end{aligned}$

Similarly, in second case,

$100 \times S_{A} (100 - T) = 50 \times S_{B} (T - 50)$

where, $T =$ Final temperature of the mixture.

$\Rightarrow 4 S_{A} (100 - T) = 2 S_{B} (T - 50)$

Using Eq. (i),

$3 S_{B} (100 - T) = 2 S_{B} (T - 50)$

$\begin{aligned} or & 300 - 3 T & = 2 T - 100 \\ or & 5 T & = 400 \\ or & T & = 80^{\circ} C \end{aligned}$

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Heat and Thermodynamics 1 Question 3

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

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Heat and Thermodynamics 1 Question 3

3. When 100g of a liquid A at 100∘C is added to 50g of a liquid B at temperature 75∘C, the temperature of the mixture becomes 90∘C. The temperature of the mixture, if 100g of liquid A at 100∘C is added to 50g of liquid B at 50∘C will be

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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