SATHEE: Gravitation 3 Question 7

Gravitation 3 Question 7

10. A geostationary satellite is orbiting the earth at a height of $6 R$ above the surface of the earth where $R$ is the radius of earth. The time period of another satellite at a height of $3.5 R$ from the surface of the earth is hours.

(1987, 2M)

True / False

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Answer:

Correct Answer: 10. $F$

Solution:

$\begin{aligned} \propto r^{3 / 2} \\ \frac{T_{2}}{T_{1}} & = {\frac{r_{2}}{r_{1}}}^{3 / 2} \\ or & T_{2} & = {\frac{r_{2}}{r_{1}}}^{3 / 2} \\ T_{1} & = {\frac{3.5 R}{7 R}}^{3 / 2} (24) h = 8.48 h \end{aligned}$

( $T_{1} = 24 h$ for geostationary satellite)

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Gravitation 3 Question 7

10. A geostationary satellite is orbiting the earth at a height of $6 R$ above the surface of the earth where $R$ is the radius of earth. The time period of another satellite at a height of $3.5 R$ from the surface of the earth is hours.

True / False

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Gravitation 3 Question 7

10. A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth where R is the radius of earth. The time period of another satellite at a height of 3.5R from the surface of the earth is hours.

True / False

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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10. A geostationary satellite is orbiting the earth at a height of $6 R$ above the surface of the earth where $R$ is the radius of earth. The time period of another satellite at a height of $3.5 R$ from the surface of the earth is hours.