Gravitation 1 Question 5
8. The numerical value of the angular velocity of rotation of the earth should be $rad / s$ in order to make the effective acceleration due to gravity at equator equal to zero.
$(1984,2 M)$
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Answer:
Correct Answer: 8. $(a, b)$
Solution:
- $g^{\prime}=g-R \omega^{2} \cos ^{2} \varphi$
At equator
$\varphi=0$
$\therefore \quad g^{\prime}=g-R \omega^{2}$
$\Rightarrow \quad 0=g-R \omega^{2}$
$$ \therefore \quad \omega=\sqrt{\frac{g}{R}}=\sqrt{\frac{9.8}{6400 \times 10^{3}}} $$
$$ =1.24 \times 10^{-3} rad / s $$
